what is the hypotenuse of a right triangle given the sides 7 cm and 9 cm round to the nearest 10th
Accepted Solution
A:
The hypotenuse is 11.4 cm longStep-by-step explanation:We have to find the hypotenuse so the other sides are:[tex]Perpendicular = P = 7\ cm\\Base = B = 9\ cm\\[/tex]Pythagoras theorem will be used to find the length of Hypotenuse[tex]H^2=P^2+B^2\\[/tex]Putting values[tex]H^2=(7)^2+(9)^2\\H^2=49+81\\H^2=130[/tex]Taking square Root on Both sides[tex]\sqrt{H^2}=\sqrt{130}\\H=11.40[/tex]Rounding off to the nearest tenth[tex]H=11.4\ cm[/tex]Hence,The hypotenuse is 11.4 cm longKeywords: Triangle, Pythagoras TheoremLearn more about Pythagoras theorem at:brainly.com/question/4401748brainly.com/question/4459688#LearnwithBrainly